An element is integral exactly when the subalgebra it generates is finite as a module. I want the notation, the mechanism, and the failure mode visible at the same time.
Definitions first
An element \(b\) is integral over \(A\) when it satisfies a monic polynomial with coefficients in \(A\). An extension \(A\subseteq B\) is integral when every \(b\in B\) has this property.
There are two layers here: the object \(\mathsf D\) and the law \(\mathsf C\). Writing them separately makes the direction of \(\Longrightarrow\) visible and keeps an accidental converse from slipping in.
A small case in full
The computation below is not a second theorem. It is a checksum for the definitions and a place to inspect the difficult LaTeX at full size.
The reusable statement
The invariant statement is the one that does not depend on a convenient choice of coordinates, representatives, basis, or enumeration.
A nearby false statement
Algebraic over a fraction field and integral over the base ring are different conditions. Denominators make many algebraic elements nonintegral.
This is enough machinery for one note: an exact object, a worked case, a structural law, and a clearly marked boundary. Each layer can now be tested independently.