Lagmental Vicfred

Ramanujan Congruences Hide in Partition Coefficients by Vicfred

Last updated: Tue 03 April 2012

Partition numbers satisfy striking congruences along three arithmetic progressions. I want the notation, the mechanism, and the failure mode visible at the same time.

The mathematical object

A modular form \(f\) on the upper half-plane transforms predictably under fractional linear maps and has a Fourier expansion in \(q=e^{2\pi i\tau}\). Its coefficients often encode arithmetic.

$$ p(5n+4)\equiv0\pmod5 $$

I read the first line as input and the second as output. The symbols \(\forall\) and \(\exists\) are not interchangeable, and neither may be upgraded silently to \(\Longleftrightarrow\).

$$ p(7n+5)\equiv0\pmod7,\qquad p(11n+6)\equiv0\pmod{11} $$

One explicit computation

The following line is the smallest calculation that still exercises the mechanism. It keeps nested delimiters and the order of operations explicit.

$$ \begin{array}{c|ccc}n&0&1&2\\\hline p(5n+4)&p(4)=5&p(9)=30&p(14)=135\end{array} $$

Why the identity matters

The invariant statement is the one that does not depend on a convenient choice of coordinates, representatives, basis, or enumeration.

$$ \begin{aligned} \mathsf{D}\;&:\quad p(5n+4)\equiv0\pmod5,\\[5pt] \mathsf{C}\;&:\quad p(7n+5)\equiv0\pmod7,\qquad p(11n+6)\equiv0\pmod{11}. \end{aligned} $$

Where it can fail

Weight, level, character, and cusp conditions are part of the definition. A formal \(q\)-series is not automatically a modular form.

$$ \boxed{\begin{gathered} \text{compact conclusion}\\[-2pt] p(7n+5)\equiv0\pmod7,\qquad p(11n+6)\equiv0\pmod{11} \end{gathered}} $$

This is enough machinery for one note: an exact object, a worked case, a structural law, and a clearly marked boundary. Each layer can now be tested independently.

This article was posted on Wed 07 January 2009. Facts and circumstances may have changed since publication.
Please contact me before jumping to conclusions if something seems wrong or unclear.