Lagmental Vicfred

The Rees Algebra Remembers an Entire Filtration by Vicfred

Adjoining a bookkeeping variable packages all powers of I into one graded algebra. The formulas are more useful when each symbol has a job rather than merely decorating the theorem.

The mathematical object

The \(I\)-adic filtration \(A\supset I\supset I^2\supset\cdots\) records increasing orders of vanishing. Completion replaces \(A\) by compatible residues modulo every \(I^n\).

$$ \mathcal R_I(A)=\bigoplus_{n\ge0}I^nt^n\subseteq A[t] $$

I keep the defining relation \(\mathsf D\) above the derived relation \(\mathsf C\). This exposes whether cancellation used \(x\ne0\) and whether the conclusion is canonical.

$$ \mathcal R_I(A)/I\mathcal R_I(A)\cong\operatorname{gr}_I(A) $$

One explicit computation

This is the algebraic core of the note. Once this line is correct, the surrounding interpretation has something solid to refer to.

$$ I=(x,y)\subset k[x,y],\qquad\mathcal R_I(A)\cong k[x,y,U,V]/(xV-yU) $$

Why the identity matters

The formula is reusable precisely because it says which pieces are structural and which belong only to the worked example.

$$ \begin{aligned} \mathsf{D}\;&:\quad \mathcal R_I(A)=\bigoplus_{n\ge0}I^nt^n\subseteq A[t],\\[5pt] \mathsf{C}\;&:\quad \mathcal R_I(A)/I\mathcal R_I(A)\cong\operatorname{gr}_I(A). \end{aligned} $$

Where it can fail

Completion and localisation answer different questions and do not commute without hypotheses. Completeness is topological data, not merely another quotient.

$$ \boxed{\begin{gathered} \text{compact conclusion}\\[-2pt] \mathcal R_I(A)/I\mathcal R_I(A)\cong\operatorname{gr}_I(A) \end{gathered}} $$

The result is compact enough to reuse without pretending that the caveat has disappeared. The worked line remains the quickest consistency check.

This article was posted on Thu 10 June 2010. Facts and circumstances may have changed since publication.
Please contact me before jumping to conclusions if something seems wrong or unclear.